(x^2x^3/4/x^5/4)^-2

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Solution for (x^2x^3/4/x^5/4)^-2 equation: 


D( x )

x^5 = 0

(((x^2*x^3)/4)/(x^5))/4 = 0

x^5 = 0

x^5 = 0

1*x^5 = 0 // : 1

x^5 = 0

x = 0

(((x^2*x^3)/4)/(x^5))/4 = 0

(((x^2*x^3)/4)/(x^5))/4 = 0

1/16 = 0

x belongs to the empty set

x in (-oo:0) U (0:+oo)

((((x^2*x^3)/4)/(x^5))/4)^-2 = 0

256 = 0

x belongs to the empty set

x belongs to the empty set

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